package com.jia.leetCode;
/**
 * Table: Project

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| project_id  | int     |
| employee_id | int     |
+-------------+---------+
主键为 (project_id, employee_id)。
employee_id 是员工表 Employee 表的外键。
Table: Employee

+------------------+---------+
| Column Name      | Type    |
+------------------+---------+
| employee_id      | int     |
| name             | varchar |
| experience_years | int     |
+------------------+---------+
主键是 employee_id。
 

编写一个SQL查询，报告所有雇员最多的项目。

查询结果格式如下所示：

Project table:
+-------------+-------------+
| project_id  | employee_id |
+-------------+-------------+
| 1           | 1           |
| 1           | 2           |
| 1           | 3           |
| 2           | 1           |
| 2           | 4           |
+-------------+-------------+

Employee table:
+-------------+--------+------------------+
| employee_id | name   | experience_years |
+-------------+--------+------------------+
| 1           | Khaled | 3                |
| 2           | Ali    | 2                |
| 3           | John   | 1                |
| 4           | Doe    | 2                |
+-------------+--------+------------------+

Result table:
+-------------+
| project_id  |
+-------------+
| 1           |
+-------------+
第一个项目有3名员工，第二个项目有2名员工。

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/project-employees-ii
著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。
 * @author Administrator
 *
 */
public class Pro1076 {
//select t.project_id  from (select project_id,count(employee_id) as 'count_emp' from Project group by project_id) as t where t.count_emp = (select count(employee_id) from Project group by project_id order by count(employee_id) DESC limit 1 )
}
